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A ball thrown vertically with a velocity of 18m/s is h meters above the ground after t seconds, where h=-5t²+18t. What is the maximum height of the ball, and when does it
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SOLVED:For Exercises 20 and 21, use the following information. If an object is propelled from ground level, the maximum height that it reaches is given by h=(v^2 sin^2 θ)/(2 g), where θis
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